If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.
Answer:
Step-by-step explanation:
Ok, so we start by setting the integral up. The integral we need to solve is:
so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:
U=5+x
du=dx
x=U-5
so when substituting the integral will look like this:
now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:
so we must define p, q, p' and q':
p=ln U
q'=U-5
and now we plug these into the formula:
Which simplifies to:
Which solves to:
so we can substitute U back, so we get:
and now we can simplify:
notice how all the constants were combined into one big constant C.
Next 7 days
amount needed-amount now=amount in each day200-148=52
52 in 7 daysdivide by 752/7=7.4285round7.43
need to earn about $7.43 each day
Answer:
5 degrees
Step-by-step explanation:
Answer:
Step-by-step explanation:
Consider Cotters paid "x" dollars:
According to given condition:
Moores paid "x+6" dollars.
Both paid total $30
Hence,
(x) + (x+6) = 30
Solving for x:
2x +6 = 30
2x = 30-6
2x = 24
x = 24/2
x = 12
So amount paid by Moores = x +6 = 12+6 = $18
*****To find number of pairs of skates: price of one pair must be given.
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