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1 year ago

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PLS HELP In circle A, secant EC and tangent BC intersect at point C. mЕВ = 171° and mBD 83°. What is mBCD?

1 answer:

liubo4ka [24]1 year ago

4 0

Answer:

∠ BCD = 44°

Step-by-step explanation:

the secant- tangent angle BCD is half the difference of the intercepted arcs, so

∠ BCD = $\frac{1}{2}$ (EB - BD) = $\frac{1}{2}$ (171 - 83)° = $\frac{1}{2}$ × 88° = 44°

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