All categories

3 years ago

Can someone help me with this? It is fractions.

Mathematics

1 answer:

ankoles [38]3 years ago

8 0

Draw 2 circles, and divide it into 8 equal sections....shade one ☝️ in each one of the pizza and you got your answer....(add the shading part.)

You might be interested in

P(4)+5>-32<br> Thank you ;)

sweet-ann [11.9K]

Answer:

Inequality- 4p + 5 >-32

Step-by-step explanation:

5 0

2 years ago

There are 4 students on a team for a relay race. How many teams can be made from 29 students?

Kaylis [27]

Answer:

7 teams, hoped this helped :)

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Is 95.045 greater than 19.545

nadezda [96]

No because in 19.545, the 9 is bigger than the 5 in 95.045 (the first 5)

3 0

2 years ago

Solve for v.<br>h = vt - 16t^2<br>What is v equal to?

maw [93]

Answer:

v = h/t + 16t

8 0

2 years ago

Using the simple random sample of weights of women from a data set, we obtain these sample statistics: nequals45 and x overbar

Tomtit [17]

Answer: (141.1, 156.48)

Step-by-step explanation:

Given sample statistics : $n=45$

$\overline{x}=148.79\text{ lb}$

$\sigma=31.37\text{ lb}$

a) We know that the best point estimate of the population mean is the sample mean.

Therefore, the best point estimate of the mean weight of all women = $\mu=148.79\text{ lb}$

b) The confidence interval for the population mean is given by :-

$\mu\ \pm E$ , where E is the margin of error.

Formula for Margin of error :-

$z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given : Significance level : $\alpha=1-0.90=0.1$

Critical value : $z_{\alpha/2}=z_{0.05}=\pm1.645$

Margin of error : $E=1.645\times\dfrac{31.37}{\sqrt{45}}\approx 7.69$

Now, the 90% confidence interval for the population mean will be :-

$148.79\ \pm\ 7.69 =(148.79-7.69\ ,\ 148.79+7.69)=(141.1,\ 156.48)$

Hence, the 90% confidence interval estimate of the mean weight of all women= (141.1, 156.48)

3 0

2 years ago