$\text{Circumference:}\\\\C=2\pi r\\\\\text{Area:}\\\\A=\pi r^2\\\\\dfrac{A}{C}=\dfrac{\pi r^2}{2\pi r}\qquad\text{cancel}\ \pi\ \text{and}\ r\\\\\dfrac{A}{C}=\dfrac{r}{2}\\\\\bold{The\ number\ of\ areas\ of\ a\ circle\ is}\ \dfrac{r}{2}\ \bold{larger\ than\ its\ circumference}.$

$\text{For a given area and circumference}:\\\\A=153.86,\ C=43.96,\ r=7\\\\\dfrac{A}{C}=\dfrac{153.86}{43.96}=3.5=\dfrac{7}{2}=\dfrac{r}{2}\\\\\dfrac{A}{C}=\dfrac{r}{2}$

4 0

2 years ago

Evaluate the following expression. 2^-2<br> Answer needs to be a fraction

Shtirlitz [24]

Answer is.........: 1/4

7 0

2 years ago

Read 2 more answers

MUST ANSWER ALL PARTS!!!!

dsp73

Hello there,

The outlier of the data set is 92. Lets first find everything with the outlier.
Mean: 60.08
Median: 57
Mode: 52
Range:46

Now let's take out the outlier of the set and see the difference.
Mean: 54.27
Median:56
Mode: 52
Range: 15

So as we can see without the outlier everything is closer together. The outlier shouldn't be included because that makes the entire set screwed up. The data is more accurate without the outlier.

Hope this helps!

6 0

2 years ago