It is 120 because first 8 goes into 96 which is 12. just add the 0 since u cant do anything else and it’s 120.
Jaymie will measure the segment and then place the point just across from the line's beginning point to create a congruent segment that shows the similarity between them.
<h3>What are the conditions of the congruent triangle?</h3>
Triangles that are equivalent in terms of size and form are known as a congruent triangle.
Segments will be built using the straightedge, and measurements will be taken using the compass. They will pick a starting point and draw a line using the straightedge, then use the compass to finish the job.
To make the congruent segment, Jaymie will measure the segment and then position the point that is opposite from the line's starting point.
Jaymie, on the other hand, will have to work a bit harder with the compass since she will need to draw a semi-circle in the original angle and transfer this measurement to the new line in order to create congruent angles.
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Answer:
Step-by-step explanation:
We want to simplify:
We need to apply the exponential property for products of powers.
Recall that:
We apply this rule to get:
This simplifies to:
We rewrite as positive index to get:
I think that it's an obtuse triangle.
The classifications of the functions are
- A vertical stretch --- p(x) = 4f(x)
- A vertical compression --- g(x) = 0.65f(x)
- A horizontal stretch --- k(x) = f(0.5x)
- A horizontal compression --- h(x) = f(14x)
<h3>How to classify each function accordingly?</h3>
The categories of the functions are given as
- A vertical stretch
- A vertical compression
- A horizontal stretch
- A horizontal compression
The general rules of the above definitions are:
- A vertical stretch --- g(x) = a f(x) if |a| > 1
- A vertical compression --- g(x) = a f(x) if 0 < |a| < 1
- A horizontal stretch --- g(x) = f(bx) if 0 < |b| < 1
- A horizontal compression --- g(x) = f(bx) if |b| > 1
Using the above rules and highlights, we have the classifications of the functions to be
- A vertical stretch --- p(x) = 4f(x)
- A vertical compression --- g(x) = 0.65f(x)
- A horizontal stretch --- k(x) = f(0.5x)
- A horizontal compression --- h(x) = f(14x)
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