Anyone know the answer??
1 answer:
Answer:
the second option
Step-by-step explanation:
in ax²+bx+c = 0:
subtract both sides by 6 to get to this form, as the right side will be left with 0
6x² + 8x - 6 = 0
here, the coefficient for x² (a) is 6, the coefficient for x (b) is 8, and the remaining number added on (c) is -6
plugging our numbers into the formula, we get
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Answer:
438,012 ways.
Step-by-step explanation:
We have been given that each coupon code will have three letters followed by two digits. The letters M, N, and O and the digits 1, 3, 5, and 7 will not be used. So, there are 23 letters and 6 digits that will be used.
Since the letters and digits can be repeated, so we will use fundamental principal of counting.
For first place, we can use 23 letters, for 2nd and 3rd place we can use 23 letters.
We can use 6 digits for 1st digit place and 6 digit for 2nd digit place as repetition is allowed.
So we can choose coupon code is following ways:
Therefore, we can choose coupon codes in 438,012 ways.