If sum of numbers (a) +(b) is 1419 and
(a) and (b) are <span>neighbors , whe have:
a + b = 1419 and b-a = 1;
<=> </span>a + b = 1419 and <span>a = b-1 ;
so we have b-1 + b = 1419 <=> 2b = 1420 <=> b=710 and a = 709
Answer: 710 and 709
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We are required to find the total milligrams if medicine the hospital can get from the three companies.
The total quantity of medicine the hospital can get from the three companies is 2.75 milligrams
There are there companies:
Company A
Company B
Company C
Company A = 1.3 milligrams
Company A is 0.9 milligrams more than Company C's
A = 0.9 + C
1.3 = 0.9 + C
1.3 - 0.9 = C
0.4 = C
C = 0.4 milligrams
Company A is also twice the difference between the weight of
Company B's supply and Company C's
A = 2(B - C)
1.3 = 2(B - 0.4)
1.3 = 2B - 0.8
1.3 + 0.8 = 2B
2.1 = 2B
Divide both sides by 2
B = 2.1/2
B = 1.05 milligrams
Therefore,
A + B + C
= 1.3 + 1.05 + 0.4
= 2.75 milligrams
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brainly.com/question/24562139
<span>Sixty-two thousand, one hundred thirty-seven.
</span>
105 different outfits can wear on an individual day
<em><u>Solution:</u></em>
I have 7 button down shirts, 5 pairs of pants and 3 pairs of shoes that I can wear to work
To find: Number of different outfits can I wear on an individual day
First he has to decide on a pair of pants and he has 5 different choices
For each of those choices he has a choice of 7 different button down shirts, so that gives him 5 x 7 = 35 different pant/shirt combinations
For each of those 35 different pant/shirt combinations, he has 3 pairs of shoes he could select, so altogether he has 35 x 3 = 105 different outfits
In short we can say,
different outfits = 7 x 5 x 3 = 105
So there 105 different outfits can wear on an individual day
Answer:
Nothng to it just mark them
Step-by-step explanation:
