Answer:
Step-by-step explanation:
Given: The radius of circle O is r, and the radius of circle X is r'.
To prove: Circle O is similar to circle X.
Proof: Move the center of the smaller circle onto the center of the largest circle. Translate the circle X by the vector XA onto circle O. The circles now have the same center.
A dilation is needed to increase the size of circle X to coincide with the circle O. A value which when multiplied by r' will create r.
The scale factor x to increase X:
⇒
A translation followed by a dilation with scale factor will map one circle to the other, thus proving the given both circles similar.
Therefore, circle O is similar to circle X.
Step-by-step explanation:
40 wpm. Because 160/4=40.
I hope that helped!
Answer:
????
Step-by-step explanation:
Where is the picture?
P.S. I am not answering this question JUST to get points, I will actually revise my answer correctly once you add in a picture! :)
He used 11/12 of sugar.
(1) I multiplied the factors and denominators by eachothers denominators
(2) I ended up with the two converted fractions: 8/12 and 3/12. The reason for this step is because if the two fractions have the smae denominator, it helps make it easier to add the fraction.
(3) I added the fractions, getting the sum of 11/12
Good question!