Well on a table of data, if the y coordinates increase a lot over a short x distance then it will be steep.
In an equation, you would put it into y = mx + b form and whatever your m is will be your slope. If m is large, it will be steep.
If only + numbers are acceptable, then the numbers divisible by 810 are represented by {810n}, where n = {0, 1, 2, 3, ... }
<h3>
Answer: 3x^3 + 11x^2 - 5x - 25</h3>
Work Shown:
yz = y(x^2+2x-5)
yz = y(x^2) + y(2x) + y(-5)
yz = x^2( y ) + 2x( y ) - 5( y )
yz = x^2( 3x+5 ) + 2x( 3x+5 ) - 5( 3x+5 )
yz = x^2*3x + x^2*5 + 2x*3x + 2x*5 - 5*3x - 5*5
yz = 3x^3 + 5x^2 + 6x^2 + 10x - 15x - 25
yz = 3x^3 + 11x^2 - 5x - 25