9514 1404 393
Answer:
(t, u, w) = (1, -2, -2)
Step-by-step explanation:
A graphing calculator makes short work of this, giving the solution as ...
(t, u, w) = (1, -2, -2)
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There are many ways to solve this "by hand." Here's one of them.
Add the first and third equations. Their sum is ...
-3t +4w = -11 . . . . . [eq4]
Add this to twice the second equation. That sum is ...
(-3t +4w) +2(-4t -2w) = (-11) +2(0)
-11t = -11
t = 1
Substituting this into the second equation gives ...
-4(1) -2w = 0
w +2 = 0 . . . . divide by -2
w = -2 . . . . add -2
Substituting for t in the third equation lets us find u.
2(1) -2u = 6
-1 +u = -3 . . . . . divide by -2
u = -2 . . . . add 1
The solution is (t, u, w) = (1, -2, -2).
Answer:
18, 19(which has two) 20(has two)
Step-by-step explanation:
Just find the ones that appear more than one time.
Formula:
a^2+b^2=c^2
c^2: Is the hypotenuse.
For a^2 and b^2, you have to multiply both it by its self.
Then, add both.
Next, you square root it.
Example:
a^2+b^2=c^2
14^2+7^2=c^2
196+49=c^2
245=c^2
15.64=c^2
Answer:
The solution is the point where the lines intersect.
The answer is (-3 , -8)
Answer:
D) e
Step-by-step explanation:
ln e^e
We know that ln x^a is the same as a ln x
e ln (e)
we know that ln e =1
e (1)
e
