1 year ago

The set of numbers 1, 5, 13, and 24 contains values for m. What values of m makes the equation below true?

Mathematics

1 answer:

Likurg_2 [28]1 year ago

7 0

Answer:

Step-by-step explanation:

Solve the equation first for "m"

6m + 12 = 42

6m = 30 (subtract 12)

m = 5 (Divide by 6)

5 is your answer

Hope this help! Please mark me brainliest, it helps!

You might be interested in

Figure out the combination.

ad-work [718]

Answer:

blue, orange, purple ,red ,blue

7 0

1 year ago

Read 2 more answers

Name: 1. Label the axes. 2. Graph: A(-3, 0) B(-2, 4) C(1, -1) Draw AABC in blue. 3. Rotate AABC 90° clockwise to create AA'B'C'

nikklg [1K]

Answer:

its B because

Step-by-step explanation:

Simplifying

41n(7x) = 8

Remove parenthesis around (7x)

41n * 7x = 8

Reorder the terms for easier multiplication:

41 * 7n * x = 8

Multiply 41 * 7

287n * x = 8

Multiply n * x

287nx = 8

Solving

287nx = 8

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Divide each side by '287x'.

n = 0.02787456446x-1

Simplifying

n = 0.02787456446x-1

3 0

1 year ago

DONT ASK FOR BRAINLIEST

KiRa [710]

2(5k+1)

2x5x2+1 =21
K=2 | 21

2x5x3+1 =31
K=3 | 31

3 0

2 years ago

Choose one of the factors of 6x^3 + 6

ivanzaharov [21]

Answer: First option is correct.

Step-by-step explanation:

Since we have given that

$6x^3+6$

Now, by factorising , we get

$6x^3+6\\=6(x^3+1)$

Now, we use the formula i.e.

$a^3+b^3=(a+b)(a^2-ab+b^2)$

By using this, we get ,

$6(x^3+1)\\=6(x+1)(x^2-x+1)$

So,

$(x+1) \text{ is the factor of }6x^3+6.$

6 0

2 years ago

Read 2 more answers

Solve for x. Someone please help me I really need it.

valkas [14]

Answer: X= 3.75

HOPE THIS HELPS:)))))

Step-by-step explanation:

5 0

1 year ago