If they get unexpected results they could note what they could've done wrong or what they could change in a next trail of experiments. Or look back and see what different happened to they could've hypothesized. There could be many different courses on what to do next.
First do 48.50-21 then divide that amount by 5. Then that’s how much each pair of socks cost so
48.50-21=27.50
27.50%5=$5.50 so rx=$5.50
Problem 7)
The answer is choice B. Only graph 2 contains an Euler circuit.
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To have a Euler circuit, each vertex must have an even number of paths connecting to it. This does not happen with graph 1 since vertex A and vertex D have an odd number of vertices (3 each). The odd vertex count makes it impossible to travel back to the starting point, while making sure to only use each edge one time only.
With graph 2, each vertex has exactly two edges attached to it. So an Euler circuit is possible here.
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Problem 8)
The answer is choice B) 5
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Work Shown:
abc base 2 = (a*2^2 + b*2^1 + c*2^0) base 10
101 base 2 = (1*2^2 + 0*2^1 + 1*2^0) base 10
101 base 2 = (1*4 + 0*2 + 1*1) base 10
101 base 2 = (4 + 0 + 1) base 10
101 base 2 = 5 base 10
I am not good in this kind of question so maybe 84?
suppose the full marks for each of them is 100 so for 5 of them it will be 500 cause if you if you multiply 100 full marks by 5 it will be 500
so the answer to this question is maybe 84?
cause if you add all of them with 84 the outcome will be 400 and if you divide the 400 by 5 it will be 80
