Answer:the weight after 225 days is
22885 kilograms
Step-by-step explanation:
The initial weight of the blue whale calf at birth is 2725 kilograms. blue whale calf gains 90 kilograms of weight each day for the first 240 days after its birth. The weight increases in arithmetic progression. This means that the first term of the sequence, a is 2725, the common difference, d is 90.
The formula for the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
n is the number of terms of the sequence.
a is the first term
d is the common difference
We want to determine its weight, T225 after 225 days after it’s birth. It means that n = 225
Therefore
T225 = 2725 + (225 - 1)90
T225 = 2725 + 224×90 = 2725 + 20160
T225 = 22885
The 24th term is 152
Step-by-step explanation:
The formula of the nth term of an arithmetic sequence is:
, where
- a is the first term
- d is the common difference between consecutive terms
The third term means n = 3
∵ 
∴ 
∵ 
= 5
- Equate the right hand sides of the third term
∴ a + 2d = 5 ⇒ (1)
The fifth term means n = 5
∵ 
∴ 
∵ 
= 19
- Equate the right hand sides of the fifth term
∴ a + 4d = 19 ⇒ (2)
Now we have a system of equations to solve it
Subtract equation (1) from equation (2) to eliminate a
∴ 2d = 14
- Divide both sides by 2
∴ d = 7
- Substitute the value of d in equation (1) to find a
∵ a + 2(7) = 5
∴ a + 14 = 5
- Subtract 14 from both sides
∴ a = -9
The twenty fourth term means n = 24
∵ a = -9 and d = 7
- Substitute the values of a and d in the formula of the nth term
∴ 
∴ 
∴ 
∴ 
The 24th term is 152
Learn more:
You can learn more about the arithmetic sequence in brainly.com/question/7221312
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Answer:
y>5/6
Step-by-step explanation:
5y+3>-7y+13
5y+7y>13-3
12y/12>10/12
y>5/6
This is an inequality, which shows where the variable y does or does not exist
from this we can say
y: (-infinity,5/6) (5/6, infinity]
or, y does not exist from (-infinity,5/6)
and does exist from (5/6, infinity]
A) In Part 1 to part 2 the bus had its farthest distance. At part 2 the bus stayed steady time went by. Part 3 to 4 was decreasing distance. part 4 was constant. Then again at part 5 the distance was increasing
B)
1 - increasing
2 - constant
3 - decreasing
4 - constant
5 - increasing
C) Non-linear, because the graph has a curve, for it to be linear it must be a straight line.
Hope this Helps :)
Answer:
-951
Step-by-step explanation:
an=a1+(n−1)d
\begin{gathered}29 = a_1 + (1-1)d\\29 = a_1\\9 = 29 + (2-1)d\\9 = 29 + d\\d = -20\\a_n = 29 -20 (n-1)\\a_n = 29 - 20n+20\\a_n = -20n + 49\\\\a_51 = -20(51) + 49 = -951\end{gathered}29=a1+(1−1)d29=a19=29+(2−1)d9=29+dd=−20an=29−20(n−1)an=29−20n+20an=−20n+49a51=−20(51)+49=−951
